49m^2+140m=+100

Solution for 49m^2+140m=+100 equation:

49m^2+140m=+100

We move all terms to the left:

49m^2+140m-(+100)=0

We add all the numbers together, and all the variables

49m^2+140m-100=0

a = 49; b = 140; c = -100;
Δ = b2-4ac
Δ = 1402-4·49·(-100)
Δ = 39200
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{39200}=\sqrt{19600*2}=\sqrt{19600}*\sqrt{2}=140\sqrt{2}$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(140)-140\sqrt{2}}{2*49}=\frac{-140-140\sqrt{2}}{98}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(140)+140\sqrt{2}}{2*49}=\frac{-140+140\sqrt{2}}{98}
$